Cosmetology schools in Jefferson, OH
3 schools within 30 miles of Jefferson, OH offer cosmetology programs, and one is in Jefferson itself. Cosmetologists in Ohio earn a median $36,260 a year, according to the BLS.
- Within 30 miles
- 3
- Closest
- 2 mi
- Public colleges
- 1
- Median pay in OH
- $36,260
What cosmetologists earn in Ohio
Median pay means half earn more and half earn less. Pay grows with experience, certifications and overtime.
- Median pay
- $36,260
- $17.43 an hour
- Typical range
- $23,520–$77,330
- 10th to 90th percentile
- Jobs in OH
- 12,890
- Job growth, 2025–35
- +7.7%
- 73,400 openings a year (U.S.)
Source: U.S. Bureau of Labor Statistics, Occupational Employment and Wage Statistics, May 2025, and Employment Projections.
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Frequently asked questions
What are the closest cosmetology schools to Jefferson?
The closest are Ashtabula County Technical and Career Campus (Jefferson, 2 mi), Brown Aveda Institute-Mentor (Mentor, 29 mi), and Laurel Technical Institute - Meadville, PA (Meadville, 29 mi). In total, 3 schools within 30 miles teach cosmetology.
How much do cosmetology programs near Jefferson cost?
For the 2 schools nearby that report it, the average yearly net price after aid ranges from $9,599 to $18,251. Ask each school for the full program cost, including tools, books and exam fees.
How much do cosmetologists make near Jefferson?
Across Ohio, the median pay is $36,260 a year, according to the U.S. Bureau of Labor Statistics. Pay varies by employer, experience and certifications.
How do I choose a cosmetology school in Jefferson?
Ask each school about accreditation, total cost after financial aid, hands-on lab hours, certification exam prep, class sizes and job placement. Request info from two or three schools so you can compare their answers side by side.
Cosmetology schools in nearby cities
- Mentor (29 mi)
- Youngstown (45 mi)
- Twinsburg (45 mi)
- Cleveland (50 mi)
- New Castle, PA (56 mi)
- Akron (60 mi)
- Alliance (60 mi)
- North Ridgeville (69 mi)